Eachnumber in the series, and any combination of those numbers is a subset of 1,3,5,7,9. To be more clear, 1 is a subset, so are 3,5,7 or 9. 1&3 are also a subset, so are 5&7 and 7&9. all of the numbers less any one of the numbers is also a subset. so 1,3,5,& & are a subset. as is 3,5,7&9. get it? Explanation This is the sequence of the odd positive integers where the nth term (an) is: an = (2n −1) for n ∈ N Answer link T_n = 2n -1 This is clearly an arithmetic sequence because the terms differ by 2 each time. To find the nth term rule we need: a value for the first term , a and a value for the common difference d . Convert1/9 times 3/5 to Decimal. Here's a little bonus calculation for you to easily work out the decimal format of the fraction we calculated. All you need to do is divide the numerator by the denominator and you can convert any fraction to decimal: 3 45 = 0.0667. Themean of 1, 3, 5, 7, 9, 11, 13 is 7. We can easily solve this problem by following the given steps. Now, we know. Mean = Sum of all observations/total number of observations. Mean of the given data = 1+3+5+6+9+11+13/7 ( The total number of observations here is 7. 3- 1 = 5 - 3 = 7 - 5 = 9 - 7 = +2 Since every preceding term is 2 more than the previous term. Thus, the required variance of this given data 1, 3, 5, 7, and 9 is +2. Learn more about arithmetic here: #SPJ2 Themean of 1, 3, 5, 7, 9, 11, 13 is 7. We can easily solve this problem by following the given steps. Mean of the given data = 1+3+5+6+9+11+13/7 ( The total number of observations here is 7. Step-by-step explanation: Mean of 3,5,7,9,11,13,15. No. of data =7. ∴Mean= 7. 3+5+7+9+11+13+15 = 7. 63 =9. Arithmetic mean (AM) H5wXOYH.

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